Showing posts with label Object. Show all posts
Showing posts with label Object. Show all posts

Dec 28, 2011

Fetching sObject Type From Record Id

"How I can get the sObject Type from Record Id?". In many requirements I do have 15-digit or 18-digit Id and I want to know the sObject to which the Id belongs to. Answer is using Global Describe we can get the sObject type.


Am getting too many emails from folks from Community Forums regarding this, so here is the generic method which will help all.


public class KeyPrefix
{
    // map to hold global describe data
    private static Map<String,Schema.SObjectType> gd;
    
    // map to store objects and their prefixes
    private static Map<String, String> keyPrefixMap;

    // to hold set of all sObject prefixes
    private static Set<String> keyPrefixSet;
    
    private static void init() {
        // get all objects from the org
        gd = Schema.getGlobalDescribe();
        
        // to store objects and their prefixes
        keyPrefixMap = new Map<String, String>{};
        
        //get the object prefix in IDs
        keyPrefixSet = gd.keySet();
        
        // fill up the prefixes map
        for(String sObj : keyPrefixSet)
        {
            Schema.DescribeSObjectResult r =  gd.get(sObj).getDescribe();
            String tempName = r.getName();
            String tempPrefix = r.getKeyPrefix();
            keyPrefixMap.put(tempPrefix, tempName);
        }
    }
    
    public static String GetKeyPrefix(String ObjId)
    {
        init() ;
        String tPrefix = ObjId;
        tPrefix = tPrefix.subString(0,3);
        
        //get the object type now
        String objectType = keyPrefixMap.get(tPrefix);
        return objectType;
    }
}


Now how you can use this? Simply save the class and pass your object Id in method "GetKeyPrefix" like this 


//a0090000002QGKu will be your object Id
System.debug('::::::: '+ KeyPrefix.GetKeyPrefix('a0090000002QGKu') );


And it will return you the object API name.

Aug 4, 2011

Inserting sObject Dynamically in Salesforce

I spend most of my time over Community, best place to learn and share knowledge. There are many questions related to sObject, and out of all a very interesting one is "How I can insert sObject record dynamically?"


I will provide a user interface with two text fields which will take "Object Name" and "Record Name" as string from user. And when I click on Save the record with Name entered should be inserted in the provided Object. Is this possible, of-course it is.


Here is the Visualforce Page code :
<apex:page controller="InsertDynamicSobjectController">
    <apex:form >
        <apex:pageBlock >
            <apex:pageBlockButtons >
                <apex:commandButton value="Save" action="{!Save}"/>
            </apex:pageBlockButtons>
            <apex:pageMessages />
            <apex:pageBlockSection >
                <apex:pageBlockSectionItem >
                    <apex:outputLabel value="Enter Object Name"/>
                    <apex:inputText value="{!ObjectName}"/>
                </apex:pageBlockSectionItem>
                <apex:pageBlockSectionItem >
                    <apex:outputLabel value="Enter Name for Record"/>
                    <apex:inputText value="{!RecordName}"/>
                </apex:pageBlockSectionItem>
            </apex:pageBlockSection>
        </apex:pageBlock>
    </apex:form>
</apex:page>

Here is the Apex Code :
public class InsertDynamicSobjectController
{
    public String ObjectName {get; set;}
    
    public String RecordName {get; set;}
    
    public InsertDynamicSobjectController()
    {
        ObjectName = '' ;
        RecordName = '' ;
    }
    
    public PageReference Save()
    {
        //use GlobalDecribe to get a list of all available Objects
        Map gd = Schema.getGlobalDescribe();
        Set objectKeys = gd.keySet();
        if(objectKeys.contains(Objectname.toLowerCase()))
        {
            try
            {
                //Creating a new sObject
                sObject sObj = Schema.getGlobalDescribe().get(ObjectName).newSObject() ;
                sObj.put('name' , RecordName) ;
                insert sObj ;
                
                PageReference pg = new PageReference('/'+sObj.Id) ;
                return pg ;
            }
            Catch(Exception e)
            {
                ApexPages.addMessages(e) ;
                return null ;
            }
        }
        else
        {
            ApexPages.addmessage(new ApexPages.message(ApexPages.severity.ERROR,'Object API name is invalid')) ;
            return null ;
        }
    }
}


Code provided is flexible and you can extend it according to your need.